libb.scriptname
- scriptname(task=None)[source]
Return name of script being run, without file extension.
- Parameters:
task (str) – Script path, defaults to sys.argv[0].
- Returns:
Script name without extension.
- Return type:
Example:
>>> scriptname(__file__) 'path' >>> scriptname() in sys.argv[0] True >>> scriptname()==sys.argv[0] False